(2x)/7=2x^2

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Solution for (2x)/7=2x^2 equation: 


x in (-oo:+oo)

(2*x)/7 = 2*x^2 // - 2*x^2

(2*x)/7-(2*x^2) = 0

(2*x)/7-2*x^2 = 0

2/7*x-2*x^2 = 0

DELTA = (2/7)^2-(-2*0*4)

DELTA = 4/49

DELTA > 0

x = ((4/49)^(1/2)-2/7)/(-2*2) or x = (-(4/49)^(1/2)-2/7)/(-2*2)

x = 0 or x = 1/7

x in { 0, 1/7 }

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